Base | Representation |
---|---|
bin | 100110001001100110111… |
… | …0100001101001111100011 |
3 | 200120020220111200002022221 |
4 | 1030103031310031033203 |
5 | 1141401301124204011 |
6 | 15052424513011511 |
7 | 1050550121060506 |
oct | 114231564151743 |
9 | 20506814602287 |
10 | 5243313116131 |
11 | 1741749619a02 |
12 | 708232b53b97 |
13 | 2c059998b02c |
14 | 141ac606713d |
15 | 915cd471971 |
hex | 4c4cdd0d3e3 |
5243313116131 has 2 divisors, whose sum is σ = 5243313116132. Its totient is φ = 5243313116130.
The previous prime is 5243313116101. The next prime is 5243313116159. The reversal of 5243313116131 is 1316113133425.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5243313116131 - 25 = 5243313116099 is a prime.
It is a super-2 number, since 2×52433131161312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5243313116101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2621656558065 + 2621656558066.
It is an arithmetic number, because the mean of its divisors is an integer number (2621656558066).
Almost surely, 25243313116131 is an apocalyptic number.
5243313116131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5243313116131 is an equidigital number, since it uses as much as digits as its factorization.
5243313116131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19440, while the sum is 34.
Adding to 5243313116131 its reverse (1316113133425), we get a palindrome (6559426249556).
The spelling of 5243313116131 in words is "five trillion, two hundred forty-three billion, three hundred thirteen million, one hundred sixteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •