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5243555525083 is a prime number
BaseRepresentation
bin100110001001101110001…
…0000111011000111011011
3200120021112101210201220021
41030103130100323013123
51141402300203300313
615052504532411311
71050556123365241
oct114233420730733
920507471721807
105243555525083
111741863438387
127082a0176b37
132c0607c73495
14141b0a328791
15915e48a678d
hex4c4dc43b1db

5243555525083 has 2 divisors, whose sum is σ = 5243555525084. Its totient is φ = 5243555525082.

The previous prime is 5243555525059. The next prime is 5243555525111. The reversal of 5243555525083 is 3805255553425.

5243555525083 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5243555525083 is a prime.

It is a super-3 number, since 3×52435555250833 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5243555525083.

It is not a weakly prime, because it can be changed into another prime (5243555525003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2621777762541 + 2621777762542.

It is an arithmetic number, because the mean of its divisors is an integer number (2621777762542).

Almost surely, 25243555525083 is an apocalyptic number.

5243555525083 is a deficient number, since it is larger than the sum of its proper divisors (1).

5243555525083 is an equidigital number, since it uses as much as digits as its factorization.

5243555525083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000000, while the sum is 52.

The spelling of 5243555525083 in words is "five trillion, two hundred forty-three billion, five hundred fifty-five million, five hundred twenty-five thousand, eighty-three".