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52500241 = 331158611
BaseRepresentation
bin1100100001000…
…1011100010001
310122210021210101
43020101130101
5101420001431
65113132401
71205146633
oct310213421
9118707711
1052500241
11276a9232
12156ba101
13ab52441
146d88a53
154920961
hex3211711

52500241 has 4 divisors (see below), whose sum is σ = 52659184. Its totient is φ = 52341300.

The previous prime is 52500229. The next prime is 52500251. The reversal of 52500241 is 14200525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52500241 - 27 = 52500113 is a prime.

It is a super-3 number, since 3×525002413 (a number of 24 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52500251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78975 + ... + 79636.

It is an arithmetic number, because the mean of its divisors is an integer number (13164796).

Almost surely, 252500241 is an apocalyptic number.

It is an amenable number.

52500241 is a deficient number, since it is larger than the sum of its proper divisors (158943).

52500241 is a wasteful number, since it uses less digits than its factorization.

52500241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 158942.

The product of its (nonzero) digits is 400, while the sum is 19.

The square root of 52500241 is about 7245.7050036556. The cubic root of 52500241 is about 374.4441923182. Note that the first 3 decimals are identical.

Adding to 52500241 its reverse (14200525), we get a palindrome (66700766).

The spelling of 52500241 in words is "fifty-two million, five hundred thousand, two hundred forty-one".

Divisors: 1 331 158611 52500241