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52503043441 = 76717684373
BaseRepresentation
bin110000111001011011…
…001101110101110001
312000112000201221201111
4300321123031311301
51330011234342231
640041454233321
73536034335332
oct607133156561
9160460657644
1052503043441
11202a26656a2
12a2131b5841
134c494c6514
142780d34289
1515744c24b1
hexc396cdd71

52503043441 has 4 divisors (see below), whose sum is σ = 52503804532. Its totient is φ = 52502282352.

The previous prime is 52503043409. The next prime is 52503043447. The reversal of 52503043441 is 14434030525.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 42054115041 + 10448928400 = 205071^2 + 102220^2 .

It is a cyclic number.

It is not a de Polignac number, because 52503043441 - 25 = 52503043409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52503043447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265470 + ... + 418903.

It is an arithmetic number, because the mean of its divisors is an integer number (13125951133).

Almost surely, 252503043441 is an apocalyptic number.

It is an amenable number.

52503043441 is a deficient number, since it is larger than the sum of its proper divisors (761091).

52503043441 is an equidigital number, since it uses as much as digits as its factorization.

52503043441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 761090.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 52503043441 its reverse (14434030525), we get a palindrome (66937073966).

The spelling of 52503043441 in words is "fifty-two billion, five hundred three million, forty-three thousand, four hundred forty-one".

Divisors: 1 76717 684373 52503043441