Base | Representation |
---|---|
bin | 10111111000000010100110… |
… | …01000101111110000100011 |
3 | 20212220020121120102102202111 |
4 | 23330001103020233300203 |
5 | 23340202244201344003 |
6 | 303355325114100151 |
7 | 14026136100206005 |
oct | 1374012310576043 |
9 | 225806546372674 |
10 | 52503075028003 |
11 | 1580247a112426 |
12 | 5a7b54571a657 |
13 | 233b0321c88c2 |
14 | cd723b854375 |
15 | 610ad36d4e6d |
hex | 2fc05322fc23 |
52503075028003 has 4 divisors (see below), whose sum is σ = 52503120739720. Its totient is φ = 52503029316288.
The previous prime is 52503075027967. The next prime is 52503075028021. The reversal of 52503075028003 is 30082057030525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52503075028003 is a prime.
It is a super-2 number, since 2×525030750280032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52503075028043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21087393 + ... + 23445346.
It is an arithmetic number, because the mean of its divisors is an integer number (13125780184930).
Almost surely, 252503075028003 is an apocalyptic number.
52503075028003 is a deficient number, since it is larger than the sum of its proper divisors (45711717).
52503075028003 is a wasteful number, since it uses less digits than its factorization.
52503075028003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45711716.
The product of its (nonzero) digits is 252000, while the sum is 40.
The spelling of 52503075028003 in words is "fifty-two trillion, five hundred three billion, seventy-five million, twenty-eight thousand, three".
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