Base | Representation |
---|---|
bin | 10111111000000010101101… |
… | …01010001101100011010010 |
3 | 20212220020202200122020210111 |
4 | 23330001112222031203102 |
5 | 23340202404314214214 |
6 | 303355335024551534 |
7 | 14026140415453066 |
oct | 1374012652154322 |
9 | 225806680566714 |
10 | 52503134132434 |
11 | 158024aa511467 |
12 | 5a7b5614825aa |
13 | 233b04152103b |
14 | cd724563baa6 |
15 | 610ad89ac5c4 |
hex | 2fc056a8d8d2 |
52503134132434 has 8 divisors (see below), whose sum is σ = 78754940321148. Its totient is φ = 26251487358720.
The previous prime is 52503134132431. The next prime is 52503134132441. The reversal of 52503134132434 is 43423143130525.
It can be written as a sum of positive squares in 2 ways, for example, as 52353863946409 + 149270186025 = 7235597^2 + 386355^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×525031341324342 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (52503134132431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39026947 + ... + 40349830.
Almost surely, 252503134132434 is an apocalyptic number.
52503134132434 is a deficient number, since it is larger than the sum of its proper divisors (26251806188714).
52503134132434 is a wasteful number, since it uses less digits than its factorization.
52503134132434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79707500.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 52503134132434 its reverse (43423143130525), we get a palindrome (95926277262959).
The spelling of 52503134132434 in words is "fifty-two trillion, five hundred three billion, one hundred thirty-four million, one hundred thirty-two thousand, four hundred thirty-four".
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