Base | Representation |
---|---|
bin | 1111010010000101011… |
… | …00100110011010111001 |
3 | 1212012101110200202022222 |
4 | 13221002230212122321 |
5 | 32100403334414243 |
6 | 1041121354253425 |
7 | 52636406560505 |
oct | 7510254463271 |
9 | 1765343622288 |
10 | 525104998073 |
11 | 19277209a097 |
12 | 85928727275 |
13 | 3a695357a16 |
14 | 1b5b54dd305 |
15 | d9d4b46168 |
hex | 7a42b266b9 |
525104998073 has 2 divisors, whose sum is σ = 525104998074. Its totient is φ = 525104998072.
The previous prime is 525104998037. The next prime is 525104998147. The reversal of 525104998073 is 370899401525.
Together with previous prime (525104998037) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 393645817744 + 131459180329 = 627412^2 + 362573^2 .
It is a cyclic number.
It is not a de Polignac number, because 525104998073 - 210 = 525104997049 is a prime.
It is not a weakly prime, because it can be changed into another prime (525104998273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262552499036 + 262552499037.
It is an arithmetic number, because the mean of its divisors is an integer number (262552499037).
Almost surely, 2525104998073 is an apocalyptic number.
It is an amenable number.
525104998073 is a deficient number, since it is larger than the sum of its proper divisors (1).
525104998073 is an equidigital number, since it uses as much as digits as its factorization.
525104998073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2721600, while the sum is 53.
The spelling of 525104998073 in words is "five hundred twenty-five billion, one hundred four million, nine hundred ninety-eight thousand, seventy-three".
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