Base | Representation |
---|---|
bin | 110000111001110111… |
… | …110111010011111011 |
3 | 12000112112212111100212 |
4 | 300321313313103323 |
5 | 1330020200201324 |
6 | 40042323221335 |
7 | 3536155224146 |
oct | 607167672373 |
9 | 160475774325 |
10 | 52510553339 |
11 | 202a6924a22 |
12 | a21581784b |
13 | 4c4ac2584a |
14 | 2781d2b05d |
15 | 1574ea770e |
hex | c39df74fb |
52510553339 has 2 divisors, whose sum is σ = 52510553340. Its totient is φ = 52510553338.
The previous prime is 52510553297. The next prime is 52510553363. The reversal of 52510553339 is 93335501525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52510553339 - 216 = 52510487803 is a prime.
It is a super-3 number, since 3×525105533393 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52510553296 and 52510553305.
It is not a weakly prime, because it can be changed into another prime (52510553239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26255276669 + 26255276670.
It is an arithmetic number, because the mean of its divisors is an integer number (26255276670).
Almost surely, 252510553339 is an apocalyptic number.
52510553339 is a deficient number, since it is larger than the sum of its proper divisors (1).
52510553339 is an equidigital number, since it uses as much as digits as its factorization.
52510553339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 303750, while the sum is 41.
The spelling of 52510553339 in words is "fifty-two billion, five hundred ten million, five hundred fifty-three thousand, three hundred thirty-nine".
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