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52512120173042 = 226256060086521
BaseRepresentation
bin10111111000010011011100…
…10001001111000111110010
320212221002221221110102010022
423330021232101033013302
523340324310231014132
6303403422431003442
714026606201524155
oct1374115621170762
9225832857412108
1052512120173042
11158062a0938802
125a8124a969582
13233bb4412452a
14cd7858c5bc9c
15610e6282ce12
hex2fc26e44f1f2

52512120173042 has 4 divisors (see below), whose sum is σ = 78768180259566. Its totient is φ = 26256060086520.

The previous prime is 52512120173027. The next prime is 52512120173053. The reversal of 52512120173042 is 24037102121525.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 52511921673121 + 198499921 = 7246511^2 + 14089^2 .

It is a junction number, because it is equal to n+sod(n) for n = 52512120172993 and 52512120173011.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13128030043259 + ... + 13128030043262.

Almost surely, 252512120173042 is an apocalyptic number.

52512120173042 is a deficient number, since it is larger than the sum of its proper divisors (26256060086524).

52512120173042 is a wasteful number, since it uses less digits than its factorization.

52512120173042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26256060086523.

The product of its (nonzero) digits is 33600, while the sum is 35.

Adding to 52512120173042 its reverse (24037102121525), we get a palindrome (76549222294567).

The spelling of 52512120173042 in words is "fifty-two trillion, five hundred twelve billion, one hundred twenty million, one hundred seventy-three thousand, forty-two".

Divisors: 1 2 26256060086521 52512120173042