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52513122131513 is a prime number
BaseRepresentation
bin10111111000010101010011…
…11111011001111000111001
320212221012112202211011202022
423330022221333121320321
523340333333231202023
6303404110102244225
714026643056162661
oct1374125177317071
9225835482734668
1052513122131513
1115806765479a5a
125a8148a426675
13233bc73898c74
14cd7911d591a1
15610ec07997c8
hex2fc2a9fd9e39

52513122131513 has 2 divisors, whose sum is σ = 52513122131514. Its totient is φ = 52513122131512.

The previous prime is 52513122131479. The next prime is 52513122131531. The reversal of 52513122131513 is 31513122131525.

Together with next prime (52513122131531) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39725439107344 + 12787683024169 = 6302812^2 + 3575987^2 .

It is a cyclic number.

It is not a de Polignac number, because 52513122131513 - 28 = 52513122131257 is a prime.

It is not a weakly prime, because it can be changed into another prime (52513122137513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26256561065756 + 26256561065757.

It is an arithmetic number, because the mean of its divisors is an integer number (26256561065757).

Almost surely, 252513122131513 is an apocalyptic number.

It is an amenable number.

52513122131513 is a deficient number, since it is larger than the sum of its proper divisors (1).

52513122131513 is an equidigital number, since it uses as much as digits as its factorization.

52513122131513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27000, while the sum is 35.

The spelling of 52513122131513 in words is "fifty-two trillion, five hundred thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, five hundred thirteen".