Base | Representation |
---|---|
bin | 110000111010000010… |
… | …000000111111101001 |
3 | 12000112201212200201012 |
4 | 300322002000333221 |
5 | 1330021340330231 |
6 | 40042500233305 |
7 | 3536216646362 |
oct | 607202007751 |
9 | 160481780635 |
10 | 52513214441 |
11 | 202a8382286 |
12 | a21669b835 |
13 | 4c4b647b6c |
14 | 2782420b69 |
15 | 1575330e2b |
hex | c3a080fe9 |
52513214441 has 2 divisors, whose sum is σ = 52513214442. Its totient is φ = 52513214440.
The previous prime is 52513214419. The next prime is 52513214449. The reversal of 52513214441 is 14441231525.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45879926416 + 6633288025 = 214196^2 + 81445^2 .
It is a cyclic number.
It is not a de Polignac number, because 52513214441 - 226 = 52446105577 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52513214398 and 52513214407.
It is not a weakly prime, because it can be changed into another prime (52513214449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26256607220 + 26256607221.
It is an arithmetic number, because the mean of its divisors is an integer number (26256607221).
Almost surely, 252513214441 is an apocalyptic number.
It is an amenable number.
52513214441 is a deficient number, since it is larger than the sum of its proper divisors (1).
52513214441 is an equidigital number, since it uses as much as digits as its factorization.
52513214441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19200, while the sum is 32.
Adding to 52513214441 its reverse (14441231525), we get a palindrome (66954445966).
The spelling of 52513214441 in words is "fifty-two billion, five hundred thirteen million, two hundred fourteen thousand, four hundred forty-one".
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