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52513399977 = 317504466659
BaseRepresentation
bin110000111010000010…
…101110010010101001
312000112202020010012220
4300322002232102221
51330021412244402
640042504224253
73536221351323
oct607202562251
9160482203186
1052513399977
11202a8499715
12a21676b089
134c4b6b144c
14278246c613
15157536adbc
hexc3a0ae4a9

52513399977 has 4 divisors (see below), whose sum is σ = 70017866640. Its totient is φ = 35008933316.

The previous prime is 52513399957. The next prime is 52513400029. The reversal of 52513399977 is 77999331525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52513399977 - 210 = 52513398953 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 52513399977.

It is not an unprimeable number, because it can be changed into a prime (52513399957) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8752233327 + ... + 8752233332.

It is an arithmetic number, because the mean of its divisors is an integer number (17504466660).

Almost surely, 252513399977 is an apocalyptic number.

It is an amenable number.

52513399977 is a deficient number, since it is larger than the sum of its proper divisors (17504466663).

52513399977 is a wasteful number, since it uses less digits than its factorization.

52513399977 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17504466662.

The product of its digits is 16074450, while the sum is 60.

The spelling of 52513399977 in words is "fifty-two billion, five hundred thirteen million, three hundred ninety-nine thousand, nine hundred seventy-seven".

Divisors: 1 3 17504466659 52513399977