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52513401360593 is a prime number
BaseRepresentation
bin10111111000010101110101…
…01000100101000011010001
320212221020021020020111001002
423330022322220211003101
523340334421222014333
6303404153515151345
714026653016452635
oct1374127250450321
9225836236214032
1052513401360593
1115806899056998
125a81547a45555
13233bcb96a3784
14cd793b082dc5
15610eda0540e8
hex2fc2baa250d1

52513401360593 has 2 divisors, whose sum is σ = 52513401360594. Its totient is φ = 52513401360592.

The previous prime is 52513401360547. The next prime is 52513401360611. The reversal of 52513401360593 is 39506310431525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52475709856144 + 37691504449 = 7244012^2 + 194143^2 .

It is a cyclic number.

It is not a de Polignac number, because 52513401360593 - 216 = 52513401295057 is a prime.

It is a super-2 number, since 2×525134013605932 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (52513401360503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26256700680296 + 26256700680297.

It is an arithmetic number, because the mean of its divisors is an integer number (26256700680297).

Almost surely, 252513401360593 is an apocalyptic number.

It is an amenable number.

52513401360593 is a deficient number, since it is larger than the sum of its proper divisors (1).

52513401360593 is an equidigital number, since it uses as much as digits as its factorization.

52513401360593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458000, while the sum is 47.

The spelling of 52513401360593 in words is "fifty-two trillion, five hundred thirteen billion, four hundred one million, three hundred sixty thousand, five hundred ninety-three".