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52521010131 = 317507003377
BaseRepresentation
bin110000111010011111…
…110000001111010011
312000120021112202101110
4300322133300033103
51330030334311011
640043335304403
73536343135342
oct607237601723
9160507482343
1052521010131
11203018172a7
12a21921b103
134c501472b5
14278348db59
151575d70ba6
hexc3a7f03d3

52521010131 has 4 divisors (see below), whose sum is σ = 70028013512. Its totient is φ = 35014006752.

The previous prime is 52521010121. The next prime is 52521010169. The reversal of 52521010131 is 13101012525.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 52521010131 - 214 = 52520993747 is a prime.

It is a super-2 number, since 2×525210101312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52521010098 and 52521010107.

It is not an unprimeable number, because it can be changed into a prime (52521010121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8753501686 + ... + 8753501691.

It is an arithmetic number, because the mean of its divisors is an integer number (17507003378).

Almost surely, 252521010131 is an apocalyptic number.

52521010131 is a deficient number, since it is larger than the sum of its proper divisors (17507003381).

52521010131 is a wasteful number, since it uses less digits than its factorization.

52521010131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17507003380.

The product of its (nonzero) digits is 300, while the sum is 21.

Adding to 52521010131 its reverse (13101012525), we get a palindrome (65622022656).

The spelling of 52521010131 in words is "fifty-two billion, five hundred twenty-one million, ten thousand, one hundred thirty-one".

Divisors: 1 3 17507003377 52521010131