Base | Representation |
---|---|
bin | 10111111000111110101100… |
… | …10011011111001011011011 |
3 | 20220000022220012110200111212 |
4 | 23330133112103133023123 |
5 | 23341214334122230133 |
6 | 303422222513413335 |
7 | 14031360465460352 |
oct | 1374372623371333 |
9 | 226008805420455 |
10 | 52535340430043 |
11 | 15815127096549 |
12 | 5a8584b26a24b |
13 | 23410a4a11083 |
14 | cd8a1cac2999 |
15 | 611871149148 |
hex | 2fc7d64df2db |
52535340430043 has 2 divisors, whose sum is σ = 52535340430044. Its totient is φ = 52535340430042.
The previous prime is 52535340429991. The next prime is 52535340430061. The reversal of 52535340430043 is 34003404353525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52535340430043 - 28 = 52535340429787 is a prime.
It is not a weakly prime, because it can be changed into another prime (52535340430843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26267670215021 + 26267670215022.
It is an arithmetic number, because the mean of its divisors is an integer number (26267670215022).
Almost surely, 252535340430043 is an apocalyptic number.
52535340430043 is a deficient number, since it is larger than the sum of its proper divisors (1).
52535340430043 is an equidigital number, since it uses as much as digits as its factorization.
52535340430043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296000, while the sum is 41.
Adding to 52535340430043 its reverse (34003404353525), we get a palindrome (86538744783568).
The spelling of 52535340430043 in words is "fifty-two trillion, five hundred thirty-five billion, three hundred forty million, four hundred thirty thousand, forty-three".
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