Base | Representation |
---|---|
bin | 10111111001001000001010… |
… | …01001101011001000011011 |
3 | 20220000211000022010100220001 |
4 | 23330210011021223020123 |
5 | 23341310240331312021 |
6 | 303424423015313431 |
7 | 14031630422556643 |
oct | 1374440511531033 |
9 | 226024008110801 |
10 | 52540421354011 |
11 | 158172a4145968 |
12 | 5a8682897b877 |
13 | 2341704564766 |
14 | cd8d8180b523 |
15 | 611a6c238091 |
hex | 2fc90526b21b |
52540421354011 has 4 divisors (see below), whose sum is σ = 52540470397800. Its totient is φ = 52540372310224.
The previous prime is 52540421353993. The next prime is 52540421354053. The reversal of 52540421354011 is 11045312404525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52540421354011 - 211 = 52540421351963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52540421954011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22878226 + ... + 25069783.
It is an arithmetic number, because the mean of its divisors is an integer number (13135117599450).
Almost surely, 252540421354011 is an apocalyptic number.
52540421354011 is a deficient number, since it is larger than the sum of its proper divisors (49043789).
52540421354011 is a wasteful number, since it uses less digits than its factorization.
52540421354011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49043788.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 52540421354011 its reverse (11045312404525), we get a palindrome (63585733758536).
The spelling of 52540421354011 in words is "fifty-two trillion, five hundred forty billion, four hundred twenty-one million, three hundred fifty-four thousand, eleven".
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