Base | Representation |
---|---|
bin | 110000111100011011… |
… | …101110110011110011 |
3 | 12000122112200221000011 |
4 | 300330123232303303 |
5 | 1330112144311011 |
6 | 40050500035351 |
7 | 3540216315463 |
oct | 607433566363 |
9 | 160575627004 |
10 | 52553510131 |
11 | 203190a5001 |
12 | a228092b57 |
13 | 4c56ab6175 |
14 | 278790dba3 |
15 | 1578b40621 |
hex | c3c6eecf3 |
52553510131 has 2 divisors, whose sum is σ = 52553510132. Its totient is φ = 52553510130.
The previous prime is 52553510101. The next prime is 52553510147. The reversal of 52553510131 is 13101535525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52553510131 - 211 = 52553508083 is a prime.
It is a super-2 number, since 2×525535101312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52553510093 and 52553510102.
It is not a weakly prime, because it can be changed into another prime (52553510101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26276755065 + 26276755066.
It is an arithmetic number, because the mean of its divisors is an integer number (26276755066).
Almost surely, 252553510131 is an apocalyptic number.
52553510131 is a deficient number, since it is larger than the sum of its proper divisors (1).
52553510131 is an equidigital number, since it uses as much as digits as its factorization.
52553510131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11250, while the sum is 31.
The spelling of 52553510131 in words is "fifty-two billion, five hundred fifty-three million, five hundred ten thousand, one hundred thirty-one".
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