Base | Representation |
---|---|
bin | 10111111100111010001000… |
… | …11000011101100000001001 |
3 | 20220111020022221110000102202 |
4 | 23332131010120131200021 |
5 | 23400422314242320313 |
6 | 304004225514405545 |
7 | 14044206623265644 |
oct | 1376350430354011 |
9 | 226436287400382 |
10 | 52670331213833 |
11 | 158673a8948383 |
12 | 5aa7a434308b5 |
13 | 2350a388685b8 |
14 | d01386d30a5b |
15 | 6151221e3558 |
hex | 2fe74461d809 |
52670331213833 has 4 divisors (see below), whose sum is σ = 52906521040128. Its totient is φ = 52434141387540.
The previous prime is 52670331213671. The next prime is 52670331213853. The reversal of 52670331213833 is 33831213307625.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52670331213833 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52670331213853) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118094912813 + ... + 118094913258.
It is an arithmetic number, because the mean of its divisors is an integer number (13226630260032).
Almost surely, 252670331213833 is an apocalyptic number.
It is an amenable number.
52670331213833 is a deficient number, since it is larger than the sum of its proper divisors (236189826295).
52670331213833 is a wasteful number, since it uses less digits than its factorization.
52670331213833 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 236189826294.
The product of its (nonzero) digits is 1632960, while the sum is 47.
The spelling of 52670331213833 in words is "fifty-two trillion, six hundred seventy billion, three hundred thirty-one million, two hundred thirteen thousand, eight hundred thirty-three".
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