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52803714044353 is a prime number
BaseRepresentation
bin11000000000110010100101…
…00111100101000111000001
320220221222121121202212010211
430000121102213211013001
523410114001243404403
6304145405155354121
714056641154530646
oct1400312247450701
9226858547685124
1052803714044353
1115908a24a96108
125b09868bb2941
1323604a4533c9c
14d079db7b7dcd
1561882c01c06d
hex3006529e51c1

52803714044353 has 2 divisors, whose sum is σ = 52803714044354. Its totient is φ = 52803714044352.

The previous prime is 52803714044293. The next prime is 52803714044399. The reversal of 52803714044353 is 35344041730825.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33348407436864 + 19455306607489 = 5774808^2 + 4410817^2 .

It is a cyclic number.

It is not a de Polignac number, because 52803714044353 - 225 = 52803680489921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52803714044297 and 52803714044306.

It is not a weakly prime, because it can be changed into another prime (52803714042353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26401857022176 + 26401857022177.

It is an arithmetic number, because the mean of its divisors is an integer number (26401857022177).

Almost surely, 252803714044353 is an apocalyptic number.

It is an amenable number.

52803714044353 is a deficient number, since it is larger than the sum of its proper divisors (1).

52803714044353 is an equidigital number, since it uses as much as digits as its factorization.

52803714044353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4838400, while the sum is 49.

The spelling of 52803714044353 in words is "fifty-two trillion, eight hundred three billion, seven hundred fourteen million, forty-four thousand, three hundred fifty-three".