Base | Representation |
---|---|
bin | 111100000100100010010000… |
… | …1010011010010100001010001 |
3 | 2120021212111010122202112202001 |
4 | 1320021010201103102201101 |
5 | 1023224110442013420441 |
6 | 5111442303033154001 |
7 | 216203560526121001 |
oct | 17011044123224121 |
9 | 2507774118675661 |
10 | 528388910295121 |
11 | 1433a7529877a87 |
12 | 4b319388b5b901 |
13 | 198aab25504a55 |
14 | 946a234378001 |
15 | 411491c734731 |
hex | 1e091214d2851 |
528388910295121 has 4 divisors (see below), whose sum is σ = 528631401766000. Its totient is φ = 528146418824244.
The previous prime is 528388910295107. The next prime is 528388910295193. The reversal of 528388910295121 is 121592019883825.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-528388910295121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (528388910295101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121245732171 + ... + 121245736528.
It is an arithmetic number, because the mean of its divisors is an integer number (132157850441500).
Almost surely, 2528388910295121 is an apocalyptic number.
It is an amenable number.
528388910295121 is a deficient number, since it is larger than the sum of its proper divisors (242491470879).
528388910295121 is a wasteful number, since it uses less digits than its factorization.
528388910295121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242491470878.
The product of its (nonzero) digits is 24883200, while the sum is 64.
The spelling of 528388910295121 in words is "five hundred twenty-eight trillion, three hundred eighty-eight billion, nine hundred ten million, two hundred ninety-five thousand, one hundred twenty-one".
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