Base | Representation |
---|---|
bin | 110001010001010110… |
… | …100100110010101001 |
3 | 12001120000010001000222 |
4 | 301101112210302221 |
5 | 1331322021324123 |
6 | 40145354335425 |
7 | 3552010442135 |
oct | 612126446251 |
9 | 161500101028 |
10 | 52904479913 |
11 | 2048922187a |
12 | a30572a575 |
13 | 4cb171b8ac |
14 | 27bc3903c5 |
15 | 159986b6c8 |
hex | c515a4ca9 |
52904479913 has 2 divisors, whose sum is σ = 52904479914. Its totient is φ = 52904479912.
The previous prime is 52904479897. The next prime is 52904479967. The reversal of 52904479913 is 31997440925.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50675412544 + 2229067369 = 225112^2 + 47213^2 .
It is a cyclic number.
It is not a de Polignac number, because 52904479913 - 24 = 52904479897 is a prime.
It is a super-4 number, since 4×529044799134 (a number of 44 digits) contains 4444 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (52904479993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26452239956 + 26452239957.
It is an arithmetic number, because the mean of its divisors is an integer number (26452239957).
Almost surely, 252904479913 is an apocalyptic number.
It is an amenable number.
52904479913 is a deficient number, since it is larger than the sum of its proper divisors (1).
52904479913 is an equidigital number, since it uses as much as digits as its factorization.
52904479913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 53.
The spelling of 52904479913 in words is "fifty-two billion, nine hundred four million, four hundred seventy-nine thousand, nine hundred thirteen".
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