Base | Representation |
---|---|
bin | 110001010100100010… |
… | …101111011001010011 |
3 | 12001200201211011210012 |
4 | 301110202233121103 |
5 | 1331424222010343 |
6 | 40154545425135 |
7 | 3553230402365 |
oct | 612442573123 |
9 | 161621734705 |
10 | 52958000723 |
11 | 20506457851 |
12 | a31b63b1ab |
13 | 4cbc83a704 |
14 | 27c5522d35 |
15 | 159e3de718 |
hex | c548af653 |
52958000723 has 2 divisors, whose sum is σ = 52958000724. Its totient is φ = 52958000722.
The previous prime is 52958000699. The next prime is 52958000749. The reversal of 52958000723 is 32700085925.
52958000723 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52958000723 - 28 = 52958000467 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (52958000923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26479000361 + 26479000362.
It is an arithmetic number, because the mean of its divisors is an integer number (26479000362).
Almost surely, 252958000723 is an apocalyptic number.
52958000723 is a deficient number, since it is larger than the sum of its proper divisors (1).
52958000723 is an equidigital number, since it uses as much as digits as its factorization.
52958000723 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 41.
The spelling of 52958000723 in words is "fifty-two billion, nine hundred fifty-eight million, seven hundred twenty-three", and thus it is an aban number.
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