Base | Representation |
---|---|
bin | 110001010101011110… |
… | …000010000111001001 |
3 | 12001201211001211222201 |
4 | 301111132002013021 |
5 | 1331442211401011 |
6 | 40200302520201 |
7 | 3553506456616 |
oct | 612536020711 |
9 | 161654054881 |
10 | 52973543881 |
11 | 20514203635 |
12 | a324896061 |
13 | 4cc2b2034b |
14 | 27c760b50d |
15 | 15a095ecc1 |
hex | c557821c9 |
52973543881 has 2 divisors, whose sum is σ = 52973543882. Its totient is φ = 52973543880.
The previous prime is 52973543863. The next prime is 52973543929. The reversal of 52973543881 is 18834537925.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41949593856 + 11023950025 = 204816^2 + 104995^2 .
It is a cyclic number.
It is not a de Polignac number, because 52973543881 - 25 = 52973543849 is a prime.
It is a super-2 number, since 2×529735438812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52973543801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26486771940 + 26486771941.
It is an arithmetic number, because the mean of its divisors is an integer number (26486771941).
Almost surely, 252973543881 is an apocalyptic number.
It is an amenable number.
52973543881 is a deficient number, since it is larger than the sum of its proper divisors (1).
52973543881 is an equidigital number, since it uses as much as digits as its factorization.
52973543881 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7257600, while the sum is 55.
The spelling of 52973543881 in words is "fifty-two billion, nine hundred seventy-three million, five hundred forty-three thousand, eight hundred eighty-one".
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