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53000110531 = 613923221477
BaseRepresentation
bin110001010111000011…
…011000000111000011
312001210200001120120201
4301113003120013003
51332021012014111
640203052150031
73554251335454
oct612703300703
9161720046521
1053000110531
11205281a9545
12a331768317
134cc8492664
1427cad6512b
1515a2e5b6c1
hexc570d81c3

53000110531 has 8 divisors (see below), whose sum is σ = 53882939664. Its totient is φ = 52117732320.

The previous prime is 53000110523. The next prime is 53000110549. The reversal of 53000110531 is 13501100035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53000110531 - 23 = 53000110523 is a prime.

It is a super-2 number, since 2×530001105312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53000110499 and 53000110508.

It is not an unprimeable number, because it can be changed into a prime (53000110561) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128565 + ... + 350041.

It is an arithmetic number, because the mean of its divisors is an integer number (6735367458).

Almost surely, 253000110531 is an apocalyptic number.

53000110531 is a deficient number, since it is larger than the sum of its proper divisors (882829133).

53000110531 is a wasteful number, since it uses less digits than its factorization.

53000110531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 225461.

The product of its (nonzero) digits is 225, while the sum is 19.

Adding to 53000110531 its reverse (13501100035), we get a palindrome (66501210566).

The spelling of 53000110531 in words is "fifty-three billion, one hundred ten thousand, five hundred thirty-one".

Divisors: 1 61 3923 221477 239303 13510097 868854271 53000110531