Base | Representation |
---|---|
bin | 110001010111000011… |
… | …111010110101010011 |
3 | 12001210200022210200021 |
4 | 301113003322311103 |
5 | 1332021031042010 |
6 | 40203055204311 |
7 | 3554252500222 |
oct | 612703726523 |
9 | 161720283607 |
10 | 53000252755 |
11 | 2052829638a |
12 | a331816697 |
13 | 4cc8512308 |
14 | 27cada0cb9 |
15 | 15a2e888da |
hex | c570fad53 |
53000252755 has 16 divisors (see below), whose sum is σ = 64269987840. Its totient is φ = 41954676192.
The previous prime is 53000252729. The next prime is 53000252779. The reversal of 53000252755 is 55725200035.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53000252755 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53000252755.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 401902 + ... + 517228.
It is an arithmetic number, because the mean of its divisors is an integer number (4016874240).
Almost surely, 253000252755 is an apocalyptic number.
53000252755 is a deficient number, since it is larger than the sum of its proper divisors (11269735085).
53000252755 is a wasteful number, since it uses less digits than its factorization.
53000252755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116298.
The product of its (nonzero) digits is 52500, while the sum is 34.
The spelling of 53000252755 in words is "fifty-three billion, two hundred fifty-two thousand, seven hundred fifty-five".
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