Base | Representation |
---|---|
bin | 111100010000010011011011… |
… | …0000011100101011100101011 |
3 | 2120111121002221021120221000111 |
4 | 1320200212312003211130223 |
5 | 1023432110412300434302 |
6 | 5115121312245115151 |
7 | 216431456352115255 |
oct | 17040466603453453 |
9 | 2514532837527014 |
10 | 530006313686827 |
11 | 14397046292721a |
12 | 4b53a9360b8ab7 |
13 | 199974c4b7c4b3 |
14 | 94c462a14ccd5 |
15 | 4141a31b240d7 |
hex | 1e209b60e572b |
530006313686827 has 4 divisors (see below), whose sum is σ = 530006536190880. Its totient is φ = 530006091182776.
The previous prime is 530006313686819. The next prime is 530006313686849. The reversal of 530006313686827 is 728686313600035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530006313686827 - 23 = 530006313686819 is a prime.
It is a super-2 number, since 2×5300063136868272 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530006313686887) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107639923 + ... + 112456060.
It is an arithmetic number, because the mean of its divisors is an integer number (132501634047720).
Almost surely, 2530006313686827 is an apocalyptic number.
530006313686827 is a deficient number, since it is larger than the sum of its proper divisors (222504053).
530006313686827 is a wasteful number, since it uses less digits than its factorization.
530006313686827 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222504052.
The product of its (nonzero) digits is 26127360, while the sum is 58.
The spelling of 530006313686827 in words is "five hundred thirty trillion, six billion, three hundred thirteen million, six hundred eighty-six thousand, eight hundred twenty-seven".
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