Base | Representation |
---|---|
bin | 111100010000010011100000… |
… | …1001101100011110010011001 |
3 | 2120111121010102022202211210000 |
4 | 1320200213001031203302121 |
5 | 1023432111303204211331 |
6 | 5115121343012443213 |
7 | 216431464114022040 |
oct | 17040470115436231 |
9 | 2514533368684700 |
10 | 530006500850841 |
11 | 143970549542323 |
12 | 4b53a988919509 |
13 | 19997524891131 |
14 | 94c4646d4d557 |
15 | 4141a432950e6 |
hex | 1e209c1363c99 |
530006500850841 has 40 divisors (see below), whose sum is σ = 904876199061120. Its totient is φ = 302849929622592.
The previous prime is 530006500850833. The next prime is 530006500850843. The reversal of 530006500850841 is 148058005600035.
530006500850841 is a `hidden beast` number, since 53 + 0 + 0 + 0 + 6 + 50 + 0 + 8 + 508 + 41 = 666.
It is not a de Polignac number, because 530006500850841 - 23 = 530006500850833 is a prime.
It is not an unprimeable number, because it can be changed into a prime (530006500850843) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1123461 + ... + 32577218.
It is an arithmetic number, because the mean of its divisors is an integer number (22621904976528).
Almost surely, 2530006500850841 is an apocalyptic number.
It is an amenable number.
530006500850841 is a deficient number, since it is larger than the sum of its proper divisors (374869698210279).
530006500850841 is a wasteful number, since it uses less digits than its factorization.
530006500850841 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33728435 (or 33728426 counting only the distinct ones).
The product of its (nonzero) digits is 576000, while the sum is 45.
The spelling of 530006500850841 in words is "five hundred thirty trillion, six billion, five hundred million, eight hundred fifty thousand, eight hundred forty-one".
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