Base | Representation |
---|---|
bin | 111100010000010011100001… |
… | …0100101111000001010111001 |
3 | 2120111121010110221100002120102 |
4 | 1320200213002211320022321 |
5 | 1023432111330121044001 |
6 | 5115121345201005145 |
7 | 216431464514560043 |
oct | 17040470245701271 |
9 | 2514533427302512 |
10 | 530006524003001 |
11 | 143970560615941 |
12 | 4b53a9946237b5 |
13 | 19997529609236 |
14 | 94c464a058a93 |
15 | 4141a45319e6b |
hex | 1e209c29782b9 |
530006524003001 has 2 divisors, whose sum is σ = 530006524003002. Its totient is φ = 530006524003000.
The previous prime is 530006524002947. The next prime is 530006524003009. The reversal of 530006524003001 is 100300425600035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 492585176947600 + 37421347055401 = 22194260^2 + 6117299^2 .
It is a cyclic number.
It is not a de Polignac number, because 530006524003001 - 26 = 530006524002937 is a prime.
It is not a weakly prime, because it can be changed into another prime (530006524003009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265003262001500 + 265003262001501.
It is an arithmetic number, because the mean of its divisors is an integer number (265003262001501).
Almost surely, 2530006524003001 is an apocalyptic number.
It is an amenable number.
530006524003001 is a deficient number, since it is larger than the sum of its proper divisors (1).
530006524003001 is an equidigital number, since it uses as much as digits as its factorization.
530006524003001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 530006524003001 its reverse (100300425600035), we get a palindrome (630306949603036).
The spelling of 530006524003001 in words is "five hundred thirty trillion, six billion, five hundred twenty-four million, three thousand, one".
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