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53000733353353 is a prime number
BaseRepresentation
bin11000000110100001100011…
…11000100110010110001001
320221122211011020100202021021
430003100301320212112021
523421331000214301403
6304420111211112441
714110114403162512
oct1403206170462611
9227584136322237
1053000733353353
1115984537285015
125b3ba92442721
132375c4216c676
14d1336ba7ba09
1561da0d9638bd
hex303431e26589

53000733353353 has 2 divisors, whose sum is σ = 53000733353354. Its totient is φ = 53000733353352.

The previous prime is 53000733353327. The next prime is 53000733353363. The reversal of 53000733353353 is 35335333700035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31022761156864 + 21977972196489 = 5569808^2 + 4688067^2 .

It is a cyclic number.

It is not a de Polignac number, because 53000733353353 - 233 = 52992143418761 is a prime.

It is not a weakly prime, because it can be changed into another prime (53000733353363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500366676676 + 26500366676677.

It is an arithmetic number, because the mean of its divisors is an integer number (26500366676677).

Almost surely, 253000733353353 is an apocalyptic number.

It is an amenable number.

53000733353353 is a deficient number, since it is larger than the sum of its proper divisors (1).

53000733353353 is an equidigital number, since it uses as much as digits as its factorization.

53000733353353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1913625, while the sum is 43.

The spelling of 53000733353353 in words is "fifty-three trillion, seven hundred thirty-three million, three hundred fifty-three thousand, three hundred fifty-three".