Base | Representation |
---|---|
bin | 11000000110100001100011… |
… | …11000100110010110001001 |
3 | 20221122211011020100202021021 |
4 | 30003100301320212112021 |
5 | 23421331000214301403 |
6 | 304420111211112441 |
7 | 14110114403162512 |
oct | 1403206170462611 |
9 | 227584136322237 |
10 | 53000733353353 |
11 | 15984537285015 |
12 | 5b3ba92442721 |
13 | 2375c4216c676 |
14 | d1336ba7ba09 |
15 | 61da0d9638bd |
hex | 303431e26589 |
53000733353353 has 2 divisors, whose sum is σ = 53000733353354. Its totient is φ = 53000733353352.
The previous prime is 53000733353327. The next prime is 53000733353363. The reversal of 53000733353353 is 35335333700035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31022761156864 + 21977972196489 = 5569808^2 + 4688067^2 .
It is a cyclic number.
It is not a de Polignac number, because 53000733353353 - 233 = 52992143418761 is a prime.
It is not a weakly prime, because it can be changed into another prime (53000733353363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500366676676 + 26500366676677.
It is an arithmetic number, because the mean of its divisors is an integer number (26500366676677).
Almost surely, 253000733353353 is an apocalyptic number.
It is an amenable number.
53000733353353 is a deficient number, since it is larger than the sum of its proper divisors (1).
53000733353353 is an equidigital number, since it uses as much as digits as its factorization.
53000733353353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1913625, while the sum is 43.
The spelling of 53000733353353 in words is "fifty-three trillion, seven hundred thirty-three million, three hundred fifty-three thousand, three hundred fifty-three".
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