Base | Representation |
---|---|
bin | 110001010111001000… |
… | …000110110000001001 |
3 | 12001210202101120000122 |
4 | 301113020012300021 |
5 | 1332021321201103 |
6 | 40203134513025 |
7 | 3554265020513 |
oct | 612710066011 |
9 | 161722346018 |
10 | 53001350153 |
11 | 20528975924 |
12 | a332065775 |
13 | 4cc880796b |
14 | 27cb1a8bb3 |
15 | 15a3103b38 |
hex | c57206c09 |
53001350153 has 4 divisors (see below), whose sum is σ = 53388221460. Its totient is φ = 52614478848.
The previous prime is 53001350113. The next prime is 53001350191. The reversal of 53001350153 is 35105310035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12595123984 + 40406226169 = 112228^2 + 201013^2 .
It is a cyclic number.
It is not a de Polignac number, because 53001350153 - 234 = 35821480969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53001350113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193435448 + ... + 193435721.
It is an arithmetic number, because the mean of its divisors is an integer number (13347055365).
Almost surely, 253001350153 is an apocalyptic number.
It is an amenable number.
53001350153 is a deficient number, since it is larger than the sum of its proper divisors (386871307).
53001350153 is a wasteful number, since it uses less digits than its factorization.
53001350153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 386871306.
The product of its (nonzero) digits is 3375, while the sum is 26.
Adding to 53001350153 its reverse (35105310035), we get a palindrome (88106660188).
The spelling of 53001350153 in words is "fifty-three billion, one million, three hundred fifty thousand, one hundred fifty-three".
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