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53001350153 = 137386871169
BaseRepresentation
bin110001010111001000…
…000110110000001001
312001210202101120000122
4301113020012300021
51332021321201103
640203134513025
73554265020513
oct612710066011
9161722346018
1053001350153
1120528975924
12a332065775
134cc880796b
1427cb1a8bb3
1515a3103b38
hexc57206c09

53001350153 has 4 divisors (see below), whose sum is σ = 53388221460. Its totient is φ = 52614478848.

The previous prime is 53001350113. The next prime is 53001350191. The reversal of 53001350153 is 35105310035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12595123984 + 40406226169 = 112228^2 + 201013^2 .

It is a cyclic number.

It is not a de Polignac number, because 53001350153 - 234 = 35821480969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53001350113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193435448 + ... + 193435721.

It is an arithmetic number, because the mean of its divisors is an integer number (13347055365).

Almost surely, 253001350153 is an apocalyptic number.

It is an amenable number.

53001350153 is a deficient number, since it is larger than the sum of its proper divisors (386871307).

53001350153 is a wasteful number, since it uses less digits than its factorization.

53001350153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 386871306.

The product of its (nonzero) digits is 3375, while the sum is 26.

Adding to 53001350153 its reverse (35105310035), we get a palindrome (88106660188).

The spelling of 53001350153 in words is "fifty-three billion, one million, three hundred fifty thousand, one hundred fifty-three".

Divisors: 1 137 386871169 53001350153