Base | Representation |
---|---|
bin | 110001010111001100… |
… | …011001001111001001 |
3 | 12001210211111200020221 |
4 | 301113030121033021 |
5 | 1332022113140231 |
6 | 40203214550041 |
7 | 3554310412360 |
oct | 612714311711 |
9 | 161724450227 |
10 | 53002474441 |
11 | 20529573594 |
12 | a332508321 |
13 | 4cc8b0c617 |
14 | 27cb3bc7d7 |
15 | 15a3276d11 |
hex | c573193c9 |
53002474441 has 8 divisors (see below), whose sum is σ = 60578913024. Its totient is φ = 45427200000.
The previous prime is 53002474429. The next prime is 53002474519. The reversal of 53002474441 is 14447420035.
53002474441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53002474441 - 27 = 53002474313 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53002474397 and 53002474406.
It is not an unprimeable number, because it can be changed into a prime (53002474141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 191185 + ... + 377566.
It is an arithmetic number, because the mean of its divisors is an integer number (7572364128).
Almost surely, 253002474441 is an apocalyptic number.
It is an amenable number.
53002474441 is a deficient number, since it is larger than the sum of its proper divisors (7576438583).
53002474441 is a wasteful number, since it uses less digits than its factorization.
53002474441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 582071.
The product of its (nonzero) digits is 53760, while the sum is 34.
Adding to 53002474441 its reverse (14447420035), we get a palindrome (67449894476).
The spelling of 53002474441 in words is "fifty-three billion, two million, four hundred seventy-four thousand, four hundred forty-one".
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