Base | Representation |
---|---|
bin | 1111011011010000111… |
… | …11010000000100100011 |
3 | 1212200002222111000001221 |
4 | 13231220133100010203 |
5 | 32141002201001123 |
6 | 1043254432035511 |
7 | 53202510444133 |
oct | 7555037200443 |
9 | 1780088430057 |
10 | 530034000163 |
11 | 194871414338 |
12 | 86883392b97 |
13 | 3ac9c5887c5 |
14 | 1b921d9cac3 |
15 | dbc272625d |
hex | 7b687d0123 |
530034000163 has 8 divisors (see below), whose sum is σ = 547141118976. Its totient is φ = 512927459400.
The previous prime is 530034000131. The next prime is 530034000179. The reversal of 530034000163 is 361000430035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530034000163 - 25 = 530034000131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530034004163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2470098 + ... + 2676088.
It is an arithmetic number, because the mean of its divisors is an integer number (68392639872).
Almost surely, 2530034000163 is an apocalyptic number.
530034000163 is a deficient number, since it is larger than the sum of its proper divisors (17107118813).
530034000163 is a wasteful number, since it uses less digits than its factorization.
530034000163 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 289025.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 530034000163 its reverse (361000430035), we get a palindrome (891034430198).
The spelling of 530034000163 in words is "five hundred thirty billion, thirty-four million, one hundred sixty-three", and thus it is an aban number.
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