Base | Representation |
---|---|
bin | 110001010111010010… |
… | …111110110100011001 |
3 | 12001210221202101222111 |
4 | 301113102332310121 |
5 | 1332023033414431 |
6 | 40203315552321 |
7 | 3554331163645 |
oct | 612722766431 |
9 | 161727671874 |
10 | 53004201241 |
11 | 2052a5429a2 |
12 | a332bbb6a1 |
13 | 4cc92955b4 |
14 | 27cb70bc25 |
15 | 15a34b87b1 |
hex | c574bed19 |
53004201241 has 2 divisors, whose sum is σ = 53004201242. Its totient is φ = 53004201240.
The previous prime is 53004201209. The next prime is 53004201259. The reversal of 53004201241 is 14210240035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52718456025 + 285745216 = 229605^2 + 16904^2 .
It is a cyclic number.
It is not a de Polignac number, because 53004201241 - 25 = 53004201209 is a prime.
It is not a weakly prime, because it can be changed into another prime (53004201841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26502100620 + 26502100621.
It is an arithmetic number, because the mean of its divisors is an integer number (26502100621).
Almost surely, 253004201241 is an apocalyptic number.
It is an amenable number.
53004201241 is a deficient number, since it is larger than the sum of its proper divisors (1).
53004201241 is an equidigital number, since it uses as much as digits as its factorization.
53004201241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 22.
Adding to 53004201241 its reverse (14210240035), we get a palindrome (67214441276).
The spelling of 53004201241 in words is "fifty-three billion, four million, two hundred one thousand, two hundred forty-one".
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