5300449963 has 4 divisors (see below), whose sum is σ = 5300739880. Its totient is φ = 5300160048.

The previous prime is 5300449961. The next prime is 5300449991. The reversal of 5300449963 is 3699440035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5300449963 - 2¹ = 5300449961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5300449961) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115545 + ... + 154762.

It is an arithmetic number, because the mean of its divisors is an integer number (1325184970).

Almost surely, 2^5300449963 is an apocalyptic number.

5300449963 is a deficient number, since it is larger than the sum of its proper divisors (289917).

5300449963 is a wasteful number, since it uses less digits than its factorization.

5300449963 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 289916.

The product of its (nonzero) digits is 349920, while the sum is 43.

The square root of 5300449963 is about 72804.1891857879. The cubic root of 5300449963 is about 1743.5627405305.

Adding to 5300449963 its reverse (3699440035), we get a palindrome (8999889998).

The spelling of 5300449963 in words is "five billion, three hundred million, four hundred forty-nine thousand, nine hundred sixty-three".