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530052354131177 is a prime number
BaseRepresentation
bin111100010000101000110111…
…0010001111100010011101001
32120111202111202220210211102002
41320201101232101330103221
51023433334210124144202
65115154405003420345
7216435006314333063
oct17041215621742351
92514674686724362
10530052354131177
11143988a3951a529
124b547844b246b5
131999b9514bb687
1494c6956a56733
154142d28a82302
hex1e2146e47c4e9

530052354131177 has 2 divisors, whose sum is σ = 530052354131178. Its totient is φ = 530052354131176.

The previous prime is 530052354131081. The next prime is 530052354131197. The reversal of 530052354131177 is 771131453250035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 493799684332816 + 36252669798361 = 22221604^2 + 6021019^2 .

It is a cyclic number.

It is not a de Polignac number, because 530052354131177 - 28 = 530052354130921 is a prime.

It is not a weakly prime, because it can be changed into another prime (530052354131197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265026177065588 + 265026177065589.

It is an arithmetic number, because the mean of its divisors is an integer number (265026177065589).

Almost surely, 2530052354131177 is an apocalyptic number.

It is an amenable number.

530052354131177 is a deficient number, since it is larger than the sum of its proper divisors (1).

530052354131177 is an equidigital number, since it uses as much as digits as its factorization.

530052354131177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1323000, while the sum is 47.

The spelling of 530052354131177 in words is "five hundred thirty trillion, fifty-two billion, three hundred fifty-four million, one hundred thirty-one thousand, one hundred seventy-seven".