530053541030441 has 4 divisors (see below), whose sum is σ = 530053841879892. Its totient is φ = 530053240180992.

The previous prime is 530053541030381. The next prime is 530053541030459. The reversal of 530053541030441 is 144030145350035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 486213304560025 + 43840236470416 = 22050245^2 + 6621196^2 .

It is a cyclic number.

It is not a de Polignac number, because 530053541030441 - 2¹⁴ = 530053541014057 is a prime.

It is a super-3 number, since 3×530053541030441³ (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530053541030395 and 530053541030404.

It is not an unprimeable number, because it can be changed into a prime (530053541030941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147766280 + ... + 151310873.

It is an arithmetic number, because the mean of its divisors is an integer number (132513460469973).

Almost surely, 2^{530053541030441} is an apocalyptic number.

It is an amenable number.

530053541030441 is a deficient number, since it is larger than the sum of its proper divisors (300849451).

530053541030441 is a wasteful number, since it uses less digits than its factorization.

530053541030441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 300849450.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 530053541030441 its reverse (144030145350035), we get a palindrome (674083686380476).

The spelling of 530053541030441 in words is "five hundred thirty trillion, fifty-three billion, five hundred forty-one million, thirty thousand, four hundred forty-one".