Base | Representation |
---|---|
bin | 11000000110110011000001… |
… | …10101011111000110001011 |
3 | 20221200201100210001121102102 |
4 | 30003121200311133012023 |
5 | 23422004201404012341 |
6 | 304424301522424015 |
7 | 14110565652651155 |
oct | 1403314065370613 |
9 | 227621323047372 |
10 | 53010111000971 |
11 | 15988509764513 |
12 | 5b4186ab0200b |
13 | 2376aa7c36197 |
14 | d139bb2b9ad5 |
15 | 61ddabd8ac9b |
hex | 303660d5f18b |
53010111000971 has 2 divisors, whose sum is σ = 53010111000972. Its totient is φ = 53010111000970.
The previous prime is 53010111000923. The next prime is 53010111001007. The reversal of 53010111000971 is 17900011101035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53010111000971 is a prime.
It is not a weakly prime, because it can be changed into another prime (53010111050971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26505055500485 + 26505055500486.
It is an arithmetic number, because the mean of its divisors is an integer number (26505055500486).
Almost surely, 253010111000971 is an apocalyptic number.
53010111000971 is a deficient number, since it is larger than the sum of its proper divisors (1).
53010111000971 is an equidigital number, since it uses as much as digits as its factorization.
53010111000971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 945, while the sum is 29.
The spelling of 53010111000971 in words is "fifty-three trillion, ten billion, one hundred eleven million, nine hundred seventy-one", and thus it is an aban number.
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