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530114403 = 37132966959
BaseRepresentation
bin11111100110001…
…110011101100011
31100221111121020210
4133212032131203
52041202130103
6124334105203
716064620020
oct3746163543
91327447223
10530114403
11252265885
1212964b203
1385a9a180
1450594547
1531815e03
hex1f98e763

530114403 has 32 divisors (see below), whose sum is σ = 899942400. Its totient is φ = 269974656.

The previous prime is 530114371. The next prime is 530114413. The reversal of 530114403 is 304411035.

It is not a de Polignac number, because 530114403 - 25 = 530114371 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a self number, because there is not a number n which added to its sum of digits gives 530114403.

It is not an unprimeable number, because it can be changed into a prime (530114413) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25563 + ... + 41396.

It is an arithmetic number, because the mean of its divisors is an integer number (28123200).

Almost surely, 2530114403 is an apocalyptic number.

530114403 is a deficient number, since it is larger than the sum of its proper divisors (369827997).

530114403 is a wasteful number, since it uses less digits than its factorization.

530114403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67011.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 530114403 is about 23024.2134067594. The cubic root of 530114403 is about 809.3254573174.

Adding to 530114403 its reverse (304411035), we get a palindrome (834525438).

The spelling of 530114403 in words is "five hundred thirty million, one hundred fourteen thousand, four hundred three".

Divisors: 1 3 7 13 21 29 39 87 91 203 273 377 609 1131 2639 7917 66959 200877 468713 870467 1406139 1941811 2611401 5825433 6093269 13592677 18279807 25243543 40778031 75730629 176704801 530114403