Base | Representation |
---|---|
bin | 11111100110001… |
… | …110011101100011 |
3 | 1100221111121020210 |
4 | 133212032131203 |
5 | 2041202130103 |
6 | 124334105203 |
7 | 16064620020 |
oct | 3746163543 |
9 | 1327447223 |
10 | 530114403 |
11 | 252265885 |
12 | 12964b203 |
13 | 85a9a180 |
14 | 50594547 |
15 | 31815e03 |
hex | 1f98e763 |
530114403 has 32 divisors (see below), whose sum is σ = 899942400. Its totient is φ = 269974656.
The previous prime is 530114371. The next prime is 530114413. The reversal of 530114403 is 304411035.
It is not a de Polignac number, because 530114403 - 25 = 530114371 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 530114403.
It is not an unprimeable number, because it can be changed into a prime (530114413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25563 + ... + 41396.
It is an arithmetic number, because the mean of its divisors is an integer number (28123200).
Almost surely, 2530114403 is an apocalyptic number.
530114403 is a deficient number, since it is larger than the sum of its proper divisors (369827997).
530114403 is a wasteful number, since it uses less digits than its factorization.
530114403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67011.
The product of its (nonzero) digits is 720, while the sum is 21.
The square root of 530114403 is about 23024.2134067594. The cubic root of 530114403 is about 809.3254573174.
Adding to 530114403 its reverse (304411035), we get a palindrome (834525438).
The spelling of 530114403 in words is "five hundred thirty million, one hundred fourteen thousand, four hundred three".
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