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53012433145 = 574259355633
BaseRepresentation
bin110001010111110010…
…011000100011111001
312001211112020122000211
4301113302120203321
51332032140330040
640204212231121
73554461150450
oct612762304371
9161745218024
1053012433145
1120534155721
12a33590b4a1
134ccabb8449
1427cc851b97
1515a40928ea
hexc57c988f9

53012433145 has 16 divisors (see below), whose sum is σ = 72720040320. Its totient is φ = 36342745344.

The previous prime is 53012433109. The next prime is 53012433211. The reversal of 53012433145 is 54133421035.

It is a cyclic number.

It is not a de Polignac number, because 53012433145 - 29 = 53012432633 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28752 + ... + 326881.

It is an arithmetic number, because the mean of its divisors is an integer number (4545002520).

Almost surely, 253012433145 is an apocalyptic number.

It is an amenable number.

53012433145 is a deficient number, since it is larger than the sum of its proper divisors (19707607175).

53012433145 is a wasteful number, since it uses less digits than its factorization.

53012433145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 359904.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 53012433145 in words is "fifty-three billion, twelve million, four hundred thirty-three thousand, one hundred forty-five".

Divisors: 1 5 7 35 4259 21295 29813 149065 355633 1778165 2489431 12447155 1514640947 7573204735 10602486629 53012433145