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530130414241 is a prime number
BaseRepresentation
bin1111011011011100011…
…11000010101010100001
31212200100200220100022201
413231232033002222201
532141201341223431
61043312154333201
753205061112551
oct7555617025241
91780320810281
10530130414241
1119491088669a
12868ab72a201
133acb654505c
141b930ad9161
15dbcae1d461
hex7b6e3c2aa1

530130414241 has 2 divisors, whose sum is σ = 530130414242. Its totient is φ = 530130414240.

The previous prime is 530130414199. The next prime is 530130414251. The reversal of 530130414241 is 142414031035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 457767262225 + 72363152016 = 676585^2 + 269004^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530130414241 is a prime.

It is a super-2 number, since 2×5301304142412 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (530130414251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265065207120 + 265065207121.

It is an arithmetic number, because the mean of its divisors is an integer number (265065207121).

Almost surely, 2530130414241 is an apocalyptic number.

It is an amenable number.

530130414241 is a deficient number, since it is larger than the sum of its proper divisors (1).

530130414241 is an equidigital number, since it uses as much as digits as its factorization.

530130414241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 530130414241 its reverse (142414031035), we get a palindrome (672544445276).

The spelling of 530130414241 in words is "five hundred thirty billion, one hundred thirty million, four hundred fourteen thousand, two hundred forty-one".