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53013419051 = 207472555233
BaseRepresentation
bin110001010111110110…
…001001010000101011
312001211121002201102212
4301113312021100223
51332032413402201
640204245315335
73554502425015
oct612766112053
9161747081385
1053013419051
112053476941a
12a336105b4b
134ccb172118
1427cca2b1b5
1515a41d9abb
hexc57d8942b

53013419051 has 4 divisors (see below), whose sum is σ = 53015995032. Its totient is φ = 53010843072.

The previous prime is 53013419029. The next prime is 53013419099. The reversal of 53013419051 is 15091431035.

53013419051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53013419051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53013418999 and 53013419017.

It is not an unprimeable number, because it can be changed into a prime (53013419651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1256870 + ... + 1298363.

It is an arithmetic number, because the mean of its divisors is an integer number (13253998758).

Almost surely, 253013419051 is an apocalyptic number.

53013419051 is a deficient number, since it is larger than the sum of its proper divisors (2575981).

53013419051 is a wasteful number, since it uses less digits than its factorization.

53013419051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2575980.

The product of its (nonzero) digits is 8100, while the sum is 32.

The spelling of 53013419051 in words is "fifty-three billion, thirteen million, four hundred nineteen thousand, fifty-one".

Divisors: 1 20747 2555233 53013419051