Base | Representation |
---|---|
bin | 110001010111111000… |
… | …100011101000000010 |
3 | 12001211122021211202121 |
4 | 301113320203220002 |
5 | 1332033044120310 |
6 | 40204311034454 |
7 | 3554511000262 |
oct | 612770435002 |
9 | 161748254677 |
10 | 53014051330 |
11 | 20535060469 |
12 | a33636ba2a |
13 | 4ccb333b56 |
14 | 27ccb537a2 |
15 | 15a42b20da |
hex | c57e23a02 |
53014051330 has 16 divisors (see below), whose sum is σ = 96574996224. Its totient is φ = 20950130800.
The previous prime is 53014051327. The next prime is 53014051331. The reversal of 53014051330 is 3315041035.
It is a junction number, because it is equal to n+sod(n) for n = 53014051295 and 53014051304.
It is not an unprimeable number, because it can be changed into a prime (53014051331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31935346 + ... + 31937005.
It is an arithmetic number, because the mean of its divisors is an integer number (6035937264).
Almost surely, 253014051330 is an apocalyptic number.
53014051330 is a deficient number, since it is larger than the sum of its proper divisors (43560944894).
53014051330 is a wasteful number, since it uses less digits than its factorization.
53014051330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63872441.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 53014051330 its reverse (3315041035), we get a palindrome (56329092365).
The spelling of 53014051330 in words is "fifty-three billion, fourteen million, fifty-one thousand, three hundred thirty".
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