Base | Representation |
---|---|
bin | 1100101000111… |
… | …1000000001001 |
3 | 10200202102021101 |
4 | 3022033000021 |
5 | 102032431122 |
6 | 5132141401 |
7 | 1212421222 |
oct | 312170011 |
9 | 120672241 |
10 | 53014537 |
11 | 27a1a674 |
12 | 15907861 |
13 | aca2564 |
14 | 7080249 |
15 | 49c3027 |
hex | 328f009 |
53014537 has 2 divisors, whose sum is σ = 53014538. Its totient is φ = 53014536.
The previous prime is 53014531. The next prime is 53014547. The reversal of 53014537 is 73541035.
It is the 2973-rd star number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 47114496 + 5900041 = 6864^2 + 2429^2 .
It is a cyclic number.
It is not a de Polignac number, because 53014537 - 23 = 53014529 is a prime.
It is a super-2 number, since 2×530145372 = 5621082266648738, which contains 22 as substring.
It is equal to p3170863 and since 53014537 and 3170863 have the same sum of digits, it is a Honaker prime.
It is not a weakly prime, because it can be changed into another prime (53014531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507268 + 26507269.
It is an arithmetic number, because the mean of its divisors is an integer number (26507269).
Almost surely, 253014537 is an apocalyptic number.
It is an amenable number.
53014537 is a deficient number, since it is larger than the sum of its proper divisors (1).
53014537 is an equidigital number, since it uses as much as digits as its factorization.
53014537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 28.
The square root of 53014537 is about 7281.1082260876. The cubic root of 53014537 is about 375.6629151292.
The spelling of 53014537 in words is "fifty-three million, fourteen thousand, five hundred thirty-seven".
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