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530146401 = 3176715467
BaseRepresentation
bin11111100110010…
…110010001100001
31100221120020010220
4133212112101201
52041204141101
6124334513253
716065112221
oct3746262141
91327506126
10530146401
11252287924
12129665829
1385aab8c5
14505a2081
1531820636
hex1f996461

530146401 has 4 divisors (see below), whose sum is σ = 706861872. Its totient is φ = 353430932.

The previous prime is 530146399. The next prime is 530146403. The reversal of 530146401 is 104641035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (530146399) and next prime (530146403).

It is a cyclic number.

It is not a de Polignac number, because 530146401 - 21 = 530146399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (530146403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88357731 + ... + 88357736.

It is an arithmetic number, because the mean of its divisors is an integer number (176715468).

Almost surely, 2530146401 is an apocalyptic number.

It is an amenable number.

530146401 is a deficient number, since it is larger than the sum of its proper divisors (176715471).

530146401 is a wasteful number, since it uses less digits than its factorization.

530146401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 176715470.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 530146401 is about 23024.9082734329. The cubic root of 530146401 is about 809.3417407679.

Adding to 530146401 its reverse (104641035), we get a palindrome (634787436).

The spelling of 530146401 in words is "five hundred thirty million, one hundred forty-six thousand, four hundred one".

Divisors: 1 3 176715467 530146401