Base | Representation |
---|---|
bin | 11000000110111100001110… |
… | …11000010110111111010001 |
3 | 20221201012010011122002200121 |
4 | 30003132013120112333101 |
5 | 23422044311434104210 |
6 | 304430440131150241 |
7 | 14111132266144453 |
oct | 1403360730267721 |
9 | 227635104562617 |
10 | 53015052644305 |
11 | 1598a615133274 |
12 | 5b42809a45381 |
13 | 23773b4971aab |
14 | d13d2970a2d3 |
15 | 61e09ab166da |
hex | 303787616fd1 |
53015052644305 has 32 divisors (see below), whose sum is σ = 64094562000000. Its totient is φ = 42094832246784.
The previous prime is 53015052644251. The next prime is 53015052644327. The reversal of 53015052644305 is 50344625051035.
It is a cyclic number.
It is not a de Polignac number, because 53015052644305 - 29 = 53015052643793 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8119931281 + ... + 8119937809.
It is an arithmetic number, because the mean of its divisors is an integer number (2002955062500).
Almost surely, 253015052644305 is an apocalyptic number.
It is an amenable number.
53015052644305 is a deficient number, since it is larger than the sum of its proper divisors (11079509355695).
53015052644305 is a wasteful number, since it uses less digits than its factorization.
53015052644305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13441.
The product of its (nonzero) digits is 1080000, while the sum is 43.
The spelling of 53015052644305 in words is "fifty-three trillion, fifteen billion, fifty-two million, six hundred forty-four thousand, three hundred five".
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