Base | Representation |
---|---|
bin | 1111011011011111000… |
… | …11000100110011111010 |
3 | 1212200102020100112021111 |
4 | 13231233203010303322 |
5 | 32141223011140010 |
6 | 1043314302430534 |
7 | 53205446261662 |
oct | 7555743046372 |
9 | 1780366315244 |
10 | 530152443130 |
11 | 194922262292 |
12 | 868b6b9244a |
13 | 3acbac88abb |
14 | 1b9339d11a2 |
15 | dbccd2058a |
hex | 7b6f8c4cfa |
530152443130 has 16 divisors (see below), whose sum is σ = 955831136904. Its totient is φ = 211715035200.
The previous prime is 530152443109. The next prime is 530152443131. The reversal of 530152443130 is 31344251035.
It can be written as a sum of positive squares in 4 ways, for example, as 390211359561 + 139941083569 = 624669^2 + 374087^2 .
It is a super-2 number, since 2×5301524431302 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 530152443092 and 530152443101.
It is not an unprimeable number, because it can be changed into a prime (530152443131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43236321 + ... + 43248580.
Almost surely, 2530152443130 is an apocalyptic number.
530152443130 is a deficient number, since it is larger than the sum of its proper divisors (425678693774).
530152443130 is a wasteful number, since it uses less digits than its factorization.
530152443130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86485521.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 530152443130 its reverse (31344251035), we get a palindrome (561496694165).
The spelling of 530152443130 in words is "five hundred thirty billion, one hundred fifty-two million, four hundred forty-three thousand, one hundred thirty".
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