Base | Representation |
---|---|
bin | 111100010001011000011000… |
… | …0101111111100010001000010 |
3 | 2120112010021011202001001102121 |
4 | 1320202300300233330101002 |
5 | 1023442022203130214132 |
6 | 5115313323010434454 |
7 | 216445251164524255 |
oct | 17042606057742102 |
9 | 2515107152031377 |
10 | 530154401023042 |
11 | 143a1824530a7a4 |
12 | 4b563584292a2a |
13 | 199a84650b2c23 |
14 | 94cb87789b09c |
15 | 41457ec843497 |
hex | 1e22c30bfc442 |
530154401023042 has 8 divisors (see below), whose sum is σ = 795451096881216. Its totient is φ = 265004035395972.
The previous prime is 530154401023007. The next prime is 530154401023043. The reversal of 530154401023042 is 240320104451035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 530154401022989 and 530154401023007.
It is not an unprimeable number, because it can be changed into a prime (530154401023043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36582548718 + ... + 36582563209.
It is an arithmetic number, because the mean of its divisors is an integer number (99431387110152).
Almost surely, 2530154401023042 is an apocalyptic number.
530154401023042 is a deficient number, since it is larger than the sum of its proper divisors (265296695858174).
530154401023042 is a wasteful number, since it uses less digits than its factorization.
530154401023042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73165115552.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 530154401023042 its reverse (240320104451035), we get a palindrome (770474505474077).
The spelling of 530154401023042 in words is "five hundred thirty trillion, one hundred fifty-four billion, four hundred one million, twenty-three thousand, forty-two".
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