Base | Representation |
---|---|
bin | 110001010111111101… |
… | …110111011110000011 |
3 | 12001211201220120020012 |
4 | 301113331313132003 |
5 | 1332033423141311 |
6 | 40204400535135 |
7 | 3554525555504 |
oct | 612775673603 |
9 | 161751816205 |
10 | 53015443331 |
11 | 20535921284 |
12 | a3369214ab |
13 | 4ccb700616 |
14 | 27ccdd6bab |
15 | 15a448978b |
hex | c57f77783 |
53015443331 has 16 divisors (see below), whose sum is σ = 53915073120. Its totient is φ = 52124117760.
The previous prime is 53015443307. The next prime is 53015443333. The reversal of 53015443331 is 13334451035.
It is a cyclic number.
It is not a de Polignac number, because 53015443331 - 26 = 53015443267 is a prime.
It is a super-2 number, since 2×530154433312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53015443333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22190285 + ... + 22192673.
It is an arithmetic number, because the mean of its divisors is an integer number (3369692070).
Almost surely, 253015443331 is an apocalyptic number.
53015443331 is a deficient number, since it is larger than the sum of its proper divisors (899629789).
53015443331 is a wasteful number, since it uses less digits than its factorization.
53015443331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3974.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 53015443331 its reverse (13334451035), we get a palindrome (66349894366).
The spelling of 53015443331 in words is "fifty-three billion, fifteen million, four hundred forty-three thousand, three hundred thirty-one".
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