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53020451230403 is a prime number
BaseRepresentation
bin11000000111000110010010…
…01010010101001011000011
320221201201001102000200120212
430003203021022111023003
523422141341003333103
6304433131541424335
714111413131314516
oct1403431112251303
9227651042020525
1053020451230403
111599193552a978
125b43875a0b0ab
132377a65268537
14d142bc6c4d7d
1561e2b4a527d8
hex3038c92952c3

53020451230403 has 2 divisors, whose sum is σ = 53020451230404. Its totient is φ = 53020451230402.

The previous prime is 53020451230399. The next prime is 53020451230447. The reversal of 53020451230403 is 30403215402035.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53020451230403 - 22 = 53020451230399 is a prime.

It is a super-2 number, since 2×530204512304032 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53020451230403.

It is not a weakly prime, because it can be changed into another prime (53020451230463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26510225615201 + 26510225615202.

It is an arithmetic number, because the mean of its divisors is an integer number (26510225615202).

Almost surely, 253020451230403 is an apocalyptic number.

53020451230403 is a deficient number, since it is larger than the sum of its proper divisors (1).

53020451230403 is an equidigital number, since it uses as much as digits as its factorization.

53020451230403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 53020451230403 its reverse (30403215402035), we get a palindrome (83423666632438).

The spelling of 53020451230403 in words is "fifty-three trillion, twenty billion, four hundred fifty-one million, two hundred thirty thousand, four hundred three".