Base | Representation |
---|---|
bin | 1111011011100101010… |
… | …11100111000101101011 |
3 | 1212200112220021022122221 |
4 | 13231302223213011223 |
5 | 32141324440343311 |
6 | 1043323421254511 |
7 | 53206655146651 |
oct | 7556253470553 |
9 | 1780486238587 |
10 | 530205012331 |
11 | 1949499a8305 |
12 | 86910704437 |
13 | 3acc8b33737 |
14 | 1b93a996dd1 |
15 | dbd2756671 |
hex | 7b72ae716b |
530205012331 has 2 divisors, whose sum is σ = 530205012332. Its totient is φ = 530205012330.
The previous prime is 530205012319. The next prime is 530205012341. The reversal of 530205012331 is 133210502035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530205012331 - 213 = 530205004139 is a prime.
It is a super-2 number, since 2×5302050123312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 530205012296 and 530205012305.
It is not a weakly prime, because it can be changed into another prime (530205012341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265102506165 + 265102506166.
It is an arithmetic number, because the mean of its divisors is an integer number (265102506166).
Almost surely, 2530205012331 is an apocalyptic number.
530205012331 is a deficient number, since it is larger than the sum of its proper divisors (1).
530205012331 is an equidigital number, since it uses as much as digits as its factorization.
530205012331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 530205012331 its reverse (133210502035), we get a palindrome (663415514366).
The spelling of 530205012331 in words is "five hundred thirty billion, two hundred five million, twelve thousand, three hundred thirty-one".
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